Rank the bond dissociation energies of the bo | vedclass

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Question

(D) The bond dissociation energy is inversely proportional to the stability of the free radical formed after homolytic cleavage of the $C-H$ bond.$1$.

Vedclass · Accepted Answer

$3 < 1 < 2$

Vedclass · Answer

(D) The bond dissociation energy is inversely proportional to the stability of the free radical formed after homolytic cleavage of the $C-H$ bond.$1$. Bond $3$ leads to a tertiary $(3^{\circ})$ radical on the cyclohexane ring,which is the most stable due to hyperconjugation and inductive effects.$2$. Bond $1$ leads to a secondary $(2^{\circ})$ radical on the cyclohexane ring,which is less stable than the $3^{\circ}$ radical.$3$. Bond $2$ leads to a primary $(1^{\circ})$ radical on the methyl group,which is the least stable.Since the stability of radicals is $3^{\circ} > 2^{\circ} > 1^{\circ}$,the bond dissociation energy order is $3 < 1 < 2$.

Rank the bond dissociation energies of the bonds indicated with the arrows (from smallest to largest).

Similar Questions

State True or False for the following statements:
$(i)$ Carbon possesses $sp^2$ hybridization in a carbocation.
$(ii)$ Carbon possesses $sp^3$ hybridization in a carbocation.
$(iii)$ $A$ carbocation is formed by homolytic fission of a bond.
$(iv)$ Carbocations are very stable.

Which of the following represents the incorrect stability order?

Which of the following carbanions is the least stable?

The correct order of stability of the given carbanions is:

With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

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